-3=x^2+3x+8

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Solution for -3=x^2+3x+8 equation: 



-3=x^2+3x+8

We move all terms to the left:

-3-(x^2+3x+8)=0

We get rid of parentheses

-x^2-3x-8-3=0

We add all the numbers together, and all the variables

-1x^2-3x-11=0

a = -1; b = -3; c = -11;
Δ = b2-4ac
Δ = -32-4·(-1)·(-11)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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